Q.

If a bus accelerates from rest for timet1 , at a constant rate'α' and then retards at a constant rate'β' for timet2 and comes to rest, thent1/t2=                              

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a

β+α2

b

βα

c

αβ+α

d

β+αα

answer is D.

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Detailed Solution

The bus starting from rest and acceleration‘α ’ in time't1' and at constant retardation ‘β ’ in time 't2'

We get v after t1 is equal to v=αt1(1)

v after t2 is equal to zero

v=βt2(2)

From (1) and (2) we get

αt1=βt2

t1t2=βα

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