If a charge on the body is 1 nC, then how many electrons are present on the body?

Given, charge on the body,

$q=\mathrm{lnC}=1\times 1\times {10}^{-9}\mathrm{C} \left(\because 1\mathrm{nC}={10}^{-9}\mathrm{C}\right)$

Charge On the electron  $e=1.6\times {10}^{-19}$

From the property of quantisation of charge, q = ne

$\Rightarrow \text{ Number of charges, }n=\frac{q}{e}=\frac{1\times {10}^{-9}}{1.6\times {10}^{-19}}$

$= 0.625 \times {10}^{-9}\times {10}^{19}$

  $= 6.25 \times {10}^9$