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Q.

If a chord of a circle  x2+y2=25 with one

 extremity at   (4,3)  subtends a right angle at the centre of this circle, then the coordinates of the other extremity of this chord can be 

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a

(3,4)

b

(4,3)

c

(3,4)

d

(3,4)

answer is D.

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Detailed Solution

detailed_solution_thumbnail

Let P be the point  (4, 3)  and Q (h, k)   be the other extremity of the chord through P. Centre of the circle is the origin 0. Then OP  is perpendicular to OQ

kh×34=1kh=43

which is satisfied by  (h,k)=(3,4)

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