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If a coil of 40 turns and area 4.0 cm² is suddenly removed from a magnetic field, it is observed that a charge of 2.0×10^–4C flows into the coil. If the resistance of the coil is 80 $Ω$ , the magnetic flux density in Wb/m² is

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answer is B.

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Detailed Solution

Given data:

Number of turns N=40

Area of the coil A=4 cm²

Charge $q = 2 \times 10^{- 4} C$

Resistance of the coil $R = 80 Ω$

Concept used: Magnetic flux

Detailed solution:

$Q_{i n} = \frac{Δ Φ}{R} = \frac{n \times BA}{R} B = \frac{Δ Q \times R}{nA} = \frac{2 \times 10^{- 4} \times 80}{40 \times 4 \times 10^{- 4}} = 1 wb / m^{2}$

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