If a conducting sphere of radius R is charged. Then the electric field at a distance r(r > R) from the centre of the sphere would be, (V = potential on the surface of the sphere)

If a sphere has a charge ‘q‘ and radius ‘R‘ potential at the surface of the sphere is

$\mathrm{v}=\frac{\mathrm{kq}}{\mathrm{R}}$

where k is a constant. Electric field at a distance r(>R) is given by, $\mathrm{E}=\frac{\mathrm{kq}}{{\mathrm{r}}^2}$

$\mathrm{E}=\frac{\mathrm{VR}}{{\mathrm{r}}^2}(\mathrm{kq}=\mathrm{VR})$