If a current loop of radius R carrying a anti-clockwise current I is placed in a plane parallel to YZ-plane, then magnetic field at a point on the axis of the loop is given by

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$B = - \frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} \hat{k}$

$B = \frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} \hat{i}$

$B = \frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} (\hat{i} \times \hat{k})$

$B = - \frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} \hat{j}$

answer is B.

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Detailed Solution

Magnetic field is perpendicular to loop i.e., perpendicular to YZ plane anticlockwise so along positive i

$B = \frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} \hat{i}$

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