If a current of 0.5amp flows through a metallic wire for 2h, then how many electrons flow through the wire

$$\begin{gathered} \mathrm{Q} = \mathrm{Ct} = (0.5\mathrm{amp})(2\times 60\times 60\sec ) =3600 \mathrm{coulombs} \\ \mathrm{no}.\mathrm{of} \mathrm{electrons} =\frac{3600}{1.6\times {10}^{-19}}=2.25\times {10}^{22} \\ (\because 1.6\times {10}^{-19}\mathrm{c}=1 \mathrm{electron}) \end{gathered}$$