If a cyclist pedalling at a speed of 5 m/s picks up a speed of 10 m/s over a distance of 50 m, then what is his acceleration?

Initial velocity, u = 5 m/s

Final velocity, v = 10 m/s

Displacement, s = 50 m

By equation of motion: 

v2 - u2 =2as

So, a = $\frac{v^2-u^2}{2s}$

         = $\frac{{10}^2-5^2}{2\times 50}$

a = $\frac{100-25}{100}$

    = 0.75 m/s²