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Q.

If a dice is thrown twice, then find the probability of getting 1 in the first throw only.


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a

 1136

b

 736

c

5 36

d

None of these 

answer is C.

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Detailed Solution

Given a dice,
Probability of getting 1 in first throw,  P(M)=16
Probability of not getting 1 in second throw, PN=56
Their independent events = M and N
Then,
The required probability,
PMN=PM×PN
PMN=16×56
PMN=536
Hence, the required probability is  536 .
Option 3 is correct.
 
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