If a dipole of dipole moment p¯ is placed in a uniform electric field E→, then torque acting on it is given by

Given: Dipole moment of the dipole =p→ and uniform electric field =E→. We know that dipole moment (p)=q.a (where q is the charge and a is dipole length). And when a dipole of dipole moment p→ is placed in uniform electric field E→, the Torque (t) = Either force x perpendicular distance bet ween the two forces =qa esinθ or τ=pEsinθ or τ→=p→×E→ (vector form)

If a dipole of dipole moment p¯ is placed in a uniform electric field E→, then torque acting on it is given by

Given: Dipole moment of the dipole =p→ and uniform electric field =E→. We know that dipole moment (p)=q.a (where q is the charge and a is dipole length). And when a dipole of dipole moment p→ is placed in uniform electric field E→, the Torque (t) = Either force x perpendicular distance bet ween the two forces =qa esinθ or τ=pEsinθ or τ→=p→×E→ (vector form)

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If a dipole of dipole moment $\bar{p}$ is placed in a uniform electric field $\vec{E},$ then torque acting on it is given by

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$\vec{τ} = \vec{p} . \vec{E}$

$\vec{τ} = \vec{p} \times \vec{E}$

$\vec{τ} = \vec{p} + \vec{E}$

$\vec{τ} = \vec{p} - \vec{E}$

answer is B.

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Detailed Solution

Given: Dipole moment of the dipole $= \vec{p}$ and uniform electric field $= \vec{E} .$ We know that dipole moment (p)=q.a (where q is the charge and a is dipole length). And when a dipole of dipole moment $\vec{p}$ is placed in uniform electric field $\vec{E},$ the Torque (t) = Either force x perpendicular distance bet ween the two forces $= q a e \sin θ$ or $τ = p E \sin θ o r \vec{τ} = \vec{p} \times \vec{E}$ (vector form)