If a→=3i^+4j^, b→=4i^ then a→+b→−3a→ is

a→+b→−3a→=a→+b→−3a→=b→−2a→=4i^−23i^+4j^=4i^−6i^−8j^=−2i^−8j^

If a→=3i^+4j^, b→=4i^ then a→+b→−3a→ is

a→+b→−3a→=a→+b→−3a→=b→−2a→=4i^−23i^+4j^=4i^−6i^−8j^=−2i^−8j^

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If $\vec{a} = 3 \hat{i} + 4 \hat{j}, \vec{b} = 4 \hat{i}$ then $(\vec{a} + \vec{b}) - 3 \vec{a}$ is

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$2 \hat{i} + 8 \hat{j}$

$- 2 \hat{i} - 8 \hat{j}$

$4 \hat{i} - 8 \hat{j}$

$- 6 \hat{i} - 8 \hat{j}$

answer is B.

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$\begin{matrix} (\vec{a} + \vec{b}) - 3 \vec{a} = \vec{a} + \vec{b} - 3 \vec{a} = \vec{b} - 2 \vec{a} \\ = 4 \hat{i} - 2 (3 \hat{i} + 4 \hat{j}) \\ = 4 \hat{i} - 6 \hat{i} - 8 \hat{j} \\ = - 2 \hat{i} - 8 \hat{j} \end{matrix}$

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If a→=3i^+4j^, b→=4i^ then a→+b→−3a→ is

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If $\vec{a} = 3 \hat{i} + 4 \hat{j}, \vec{b} = 4 \hat{i}$ then $(\vec{a} + \vec{b}) - 3 \vec{a}$ is