If a fair coin is tossed 15 times, then probability of getting heads as many times in the first ten throws as in the last five throws is 

In last five thrown can there be 0, 1, 2, 3, 4, or 5 heads and the same should be in first ten throws. 

$\therefore n\left(E\right){=}^{10}{C}_0{.}^5{C}_0{+}^{10}{C}_1{.}^5{C}_1{+}^{10}{C}_2{.}^5{C}_2{+}^{10}{C}_3{.}^5{C}_3{+}^{10}{C}_4{.}^5{C}_4{+}^{10}{C}_5{.}^5{C}_5$

$=3003$

$n\left(s\right)=2^{15}=32768$