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If a gas absorbs 200 J of heat and expands by $500 {cm}^{3}$ against a constant pressure of $2 \times 10^{5} {Nm}^{- 2},$ then change in internal energy is

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$- 300 J$

$+ 100 J$

$- 100 J$

$+ 300 J$

answer is C.

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Detailed Solution

$q = 200 J$

$∆ V = 500 {cm}^{3}$

$p = 2 \times 10^{5} {Nm}^{- 2}$

$1 cm = 10^{- 2} m$

$∆ V = 500 \times 10^{- 6} m^{3}$

$w = - p ∆ V$

$= - 2 \times 10^{5} N / m^{2} \times 500 \times 10^{- 6} m^{3}$

=-100NM

$w = - 100 J$

$∆ E = + 100 J$

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