If a heater coli rated 1kW, 220V is connected in series with an electric bulb of 100W, 220V and are supplied 200V, power consumed by the bulb in this circuit is

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$68.4 W$

$45.8 W$

$10.6 W$

$29.5 W$

answer is A.

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Detailed Solution

$P = \frac{V^{2}}{R} \Rightarrow R = \frac{V^{2}}{P}$

$R_{1} = \frac{220^{2}}{1000} Ω, R_{2} = \frac{220^{2}}{100} Ω$

$R_{s e r i e s} = R_{1} + R_{2} = \frac{220^{2} \times 11}{1000} Ω$

$C u r r e n t : i = \frac{V}{R_{s e r i e s}} = \frac{200 \times 1000}{220^{2} \times 11}$

Power consumed by bulb $= i^{2} R_{2} ≃ 68.4 W$

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