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If $A = \hat{i} + 2 \hat{j} + 3 \hat{k}$ , $B = 3 \hat{i} + 4 \hat{j} + 7 \hat{k}$ , and $C = 2 \hat{i} + 3 \hat{j} + 5 \hat{k}$ are collinear then the ratio in which B divides $\overset{⇀}{A C}$ is

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4:1 internally

2:1 externally

4:1 externally

2:1 internally

answer is A.

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Detailed Solution

$A = (1, 2, 3), B = (3, 4, 7), C = (2, 3, 5)$

B, divides AC in the ratio = 1-3:3-2=-2 : 1 OR
2:1 externally

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