If a¯=i¯+j¯+k¯ ,a¯·b¯=1,a¯×b¯=2i¯+j¯-3k¯ then 3b→ is

a¯=(1,1,1)a¯b¯=1,a¯×b¯=(2,1,−3)3b¯=(x,y,z)=1 x+y+z=3(5,- 4, 2) satisfies equation

If a¯=i¯+j¯+k¯ ,a¯·b¯=1,a¯×b¯=2i¯+j¯-3k¯ then 3b→ is

a¯=(1,1,1)a¯b¯=1,a¯×b¯=(2,1,−3)3b¯=(x,y,z)=1 x+y+z=3(5,- 4, 2) satisfies equation

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If $\bar{a} = \bar{i} + \bar{j} + \bar{k}, \bar{a} \cdot \bar{b} = 1, \bar{a} \times \bar{b} = 2 \bar{i} + \bar{j} - 3 \bar{k}$ then $3 \vec{b}$ is

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$5 \bar{i} - 4 \bar{j} + 2 \bar{k}$

$3 \bar{i} - 6 \bar{j}$

$4 \bar{i} - 5 \bar{j} + \bar{k}$

$4 \bar{i} + \bar{j} + \bar{k}$

answer is A.

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$\begin{array}{l} \bar{a} = (1, 1, 1) \bar{a} \bar{b} = 1, \\ \bar{a} \times \bar{b} = (2, 1, - 3) \\ 3 \bar{b} = (x, y, z) = 1 x + y + z = 3 \end{array}$

(5,- 4, 2) satisfies equation

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If a¯=i¯+j¯+k¯ ,a¯·b¯=1,a¯×b¯=2i¯+j¯-3k¯ then 3b→ is

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If $\bar{a} = \bar{i} + \bar{j} + \bar{k}, \bar{a} \cdot \bar{b} = 1, \bar{a} \times \bar{b} = 2 \bar{i} + \bar{j} - 3 \bar{k}$ then $3 \vec{b}$ is