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Q.

If a I-order reaction is completed to the extent of 60% and 20% in time intervals, t₁ and t₂, what is the ratio t₁: t₂?

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a

8.33

b

6.32

c

4.11

d

5.58

answer is C.

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Detailed Solution

The ratios of times is given below;

$\frac{t_{1}}{t_{2}} = \frac{\ln (\frac{100}{40})}{\ln (\frac{100}{80})} \frac{t_{1}}{t_{2}} = = 4.11$

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