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Q.

If A is an angle then $\tan 2 A =$

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a

$\frac{\cos 2 A}{\sin 2 A}$

b

$\frac{\sin 2 A}{\cos 2 A}$

c

$\frac{2 \tan A}{1 + \tan^{2} A}$

d

$\frac{2 \tan A}{1 - \tan^{2} A}$

answer is A, B.

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Detailed Solution

$\tan 2 A = \frac{\sin 2 A}{\cos 2 A} = \frac{2 \tan A}{1 - \tan^{2} A}$

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If A is an angle then tan2A=