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Q.

If A is non - singular matrix of order n×n,

 Column 1 Column 2
(A)adj (A-1) is(P)A (det A)n-2
(B)det (adj (A-1)) is(Q)(det A)n-1(adj A)
(C)adj (adj A) is(R)adj (adj A)(det A)n-1
(D)adj (A det (A)) is

(S)

(T)

det A1-n

Adet A

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a

(A)=(R,T) ; (B) = (S) ; (C) = (P) ; (D) = (Q,T)

b

(A)=(R,T) ; (B) = (S) ; (C) = (P) ; (D) = (Q)

c

(A)= (T) ; (B) = (S) ; (C) = (P) ; (D) = (Q)

d

(A)=(R,T) ; (B) = (S) ; (C) = (P) ; (D) = (S)

answer is A.

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Detailed Solution

(A)=(R,T); (B)=(S); (C) =(P); (D) =(Q) (A) adj (A-1)=(A-1)-1det(A-1)=Adet(A)  (B) det (adj A-1))=(det A-1)n-1                                 =1(det A)n-1=(det A)1-n   (C) adj [adj A]=A(det A)n-2  (D) adj(A det A)=(det A)n-1(adj A)

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