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If A is the set of positive divisors of the number 15, B is the set of prime numbers smaller than 10 and C is the set of positive even numbers smaller than 9, then ( $(A \cup C) \cap B$ is the se

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{1,3, 5}

{1,2,3}

{2,3, 5}

{2, 5}

answer is C.

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Detailed Solution

$\begin{array}{l} A = {1, 3, 5, 15}, B = {2, 3, 5, 7}, C = {2, 4, 6, 8} \\ ∴ A \cup C = {1, 2, 3, 4, 5, 6, 8, 15} \end{array}$
and $(A \cup C) \cap B = {2, 3, 5}$

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