If A=k/2000l/3000m/4 and A−1=[1/20001/30001/4] then 10(k+l+m)=

A=[k/2000l/3000m/4]⇒A−1=[2/k0003/l0004/m]k=4;l=9;m=16k+l+m=29

If A=k/2000l/3000m/4 and A−1=[1/20001/30001/4] then 10(k+l+m)=

A=[k/2000l/3000m/4]⇒A−1=[2/k0003/l0004/m]k=4;l=9;m=16k+l+m=29

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If $A = [\begin{matrix} k / 2 & 0 & 0 \\ 0 & l / 3 & 0 \\ 0 & 0 & m / 4 \end{matrix}]$ and $A^{- 1} = [\begin{matrix} 1 / 2 & 0 & 0 \\ 0 & 1 / 3 & 0 \\ 0 & 0 & 1 / 4 \end{matrix}]$ then $10 (k + l + m) =$

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Detailed Solution

$A = [\begin{matrix} k / 2 & 0 & 0 \\ 0 & l / 3 & 0 \\ 0 & 0 & m / 4 \end{matrix}] \Rightarrow A^{- 1}$

$= [\begin{matrix} 2 / k & 0 & 0 \\ 0 & 3 / l & 0 \\ 0 & 0 & 4 / m \end{matrix}]$

$k = 4; l = 9; m = 16$

$k + l + m = 29$

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If A=k/2000l/3000m/4 and A−1=[1/20001/30001/4] then 10(k+l+m)=

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If $A = [\begin{matrix} k / 2 & 0 & 0 \\ 0 & l / 3 & 0 \\ 0 & 0 & m / 4 \end{matrix}]$ and $A^{- 1} = [\begin{matrix} 1 / 2 & 0 & 0 \\ 0 & 1 / 3 & 0 \\ 0 & 0 & 1 / 4 \end{matrix}]$ then $10 (k + l + m) =$