If a lighter body (mass M1 and velocity V1) and a heavier body (mass M2 and velocity V2) have the same kinetic energy, then

P=2 mE. If kinetic energy are equal then P∝mi.e., heavier body posses large momentumAs M1<M2 therefore M1V1<M2V2

If a lighter body (mass M1 and velocity V1) and a heavier body (mass M2 and velocity V2) have the same kinetic energy, then

P=2 mE. If kinetic energy are equal then P∝mi.e., heavier body posses large momentumAs M1<M2 therefore M1V1<M2V2

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If a lighter body (mass M₁ and velocity V₁) and a heavier body (mass M₂ and velocity V₂) have the same kinetic energy, then

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$M_{2} V_{2} > M_{1} V_{1}$

$M_{2} V_{1} = M_{1} V_{2}$

$M_{2} V_{2} < M_{1} V_{1}$

$M_{2} V_{2} = M_{1} V_{1}$

answer is D.

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Detailed Solution

$P = \sqrt{2 mE} .$ If kinetic energy are equal then $P \propto \sqrt{m}$
i.e., heavier body posses large momentum
As $M_{1} < M_{2}$ therefore $M_{1} V_{1} < M_{2} V_{2}$

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If a lighter body (mass M1 and velocity V1) and a heavier body (mass M2 and velocity V2) have the same kinetic energy, then

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If a lighter body (mass M₁ and velocity V₁) and a heavier body (mass M₂ and velocity V₂) have the same kinetic energy, then