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If a metal is exposed with light of wavelength $λ$ , the maximum. kinetic energy produced is found to be 2 e V. When the same metal is exposed to a wavelength $\frac{λ}{5}$ the maximum kinetic energy was 5 found to be 14 eV. Find the value of work function (in eV).

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Detailed Solution

It is known that

$\frac{h c}{λ} = W + 2; \frac{5 h c}{λ} = W + 14 \Rightarrow W = 1 eV$

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