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If a number is a selected at random from first 100 natural numbers then the probability that the number is a two digited number with atleast one even digit either at the begining or ending is

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$\frac{13}{20}$

$\frac{69}{100}$

$\frac{7}{10}$

$\frac{1}{2}$

answer is A.

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Detailed Solution

$n (S) = 100$

E= a number is two digit number with at least one even digit either begining or ending

$\begin{array}{rcl} n (E) & = & 45 + 5 \times 5 + 4 \times 5 = 65 \\ p (E) & = & \frac{65}{100} \end{array}$

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