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Q.

If a particle having an initial velocity of20 ms1 , moves with a uniform acceleration of10 ms2, then the distance covered by it when it attains a final velocity of 80 ms1is     

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a

250 m

b

200 m

c

300 m

d

150 m

answer is D.

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Detailed Solution

Initial velocityu=20ms1, Accelerationa=10ms2, Final velocityv=80ms1

s =?

We know v2u2=2as

s=v2u22a=(80)2(20)22(10)=300m

s=300m

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