If a particle is moving along a straight line and following is the graph showing acceleration varying with time then choose correct statement
At  $t=0,x=o,and{v}_0=7m/s$

Are under a – t graph gives change in velocity from this, it can be inferred that the velocity changes by more than 7 m/s, so it has to be zero once before the particle changes direction of motion.

initially acceleration is -ive and velocity is +ive. ie the bosy is decelerating. And comes to rest after some time. Changes its direction in opposite side.

 $$\begin{gathered} area undet Vt graph give change in velocity \\ \Delta V for first 4seconds=\frac{1}{2}\times 4\times -4=-8m/s \end{gathered}$$

when acceleration and velocity are +ive, body moves in initial direction. 

Object cannot reach initial position.
However the displacement of body can never be zero as the particle continues to move further