If a pea plant produces 1616 plants in ${\mathrm{F}}_2$ generation with respect to dihybrid cross for seed color and shape, how many of them have parental genotypes?

In ${\mathrm{F}}_2$ generation the probability of formation of dominant parent with genotype RR YY is $\frac{1}{16}$ and another parent with rr yy genotype also there is formation of $\frac{1}{16}$. The sum of these probabilities is $\frac{1}{16}+\frac{1}{16} = \frac{1}{8}$. The number of plants formed with the genotype of parents would be $\frac{1616}{8} = 202$.