If a person is pushing a box inside a moving train, the work done in the frame of earth will be:s0→ = displacement of the train relative to the ground.s→ = displacement of the box w.r.t train

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If a person is pushing a box inside a moving train, the work done in the frame of earth will be:

$\vec{s_{0}}$ = displacement of the train relative to the ground.

$\vec{s}$ = displacement of the box w.r.t train

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$\vec{F} . (\vec{s} + \vec{s_{0}})$

$\vec{F} . \vec{s}$

$\vec{F} . \vec{s_{0}}$

answer is B.

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Detailed Solution

Displacement w.r.t ground = $\vec{s} + \vec{s_{0}}$

Since train is moving with constant velocity net force acting on block is = $\vec{F}$ .

Therefore work done = $\vec{F} . (\vec{s} + \vec{s_{0}})$

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