If a person of mass $60 \mathrm{kg}$ goes to the surface of the moon. What will be its weight on the surface of the moon. Take $\mathrm{g}=9.8\mathrm{m}/{\mathrm{s}}^2$

Given,

Mass of person $=10 \mathrm{kg}$

Acceleration due to gravity on earth $=9.8\mathrm{m}/{\mathrm{s}}^2$

Acceleration due to gravity on the moon $=\frac{9.8}{6}\mathrm{m}/{\mathrm{s}}^2$

as    ${\mathrm{g}}_{\mathrm{m}}=\frac{1}{6}\times {\mathrm{g}}_{\mathrm{e}}$

Now, Weight on the moon $={\mathrm{mg}}_{\mathrm{m}}$

$\Rightarrow {\mathrm{W}}_{\mathrm{m}}=60\times \frac{9.8}{6}$

$=98\mathrm{N}$