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If a potential difference V is applied across a conductor, the drift speed of an electron in it is v. If the potential difference is doubled, then the drift speed of the electron becomes nv, where n is _________

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answer is 2.

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Detailed Solution

$v_{d} = \frac{I}{neA}$

$Now, I = V / R$

$So, v_{d} = \frac{V}{neAR}$

$v_{d}^{'} = \frac{2 I}{neA} = 2 v_{d}$
So where V is doubled drift speed is also doubled

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