If a radioactive sample of mass m reduces to m16 in time t, half life of that specimen is

If x is the no of half life time then m=m02x=m016=m024No.of half live 4HereNow t=xT1/2T1/2=t4

If a radioactive sample of mass m reduces to m16 in time t, half life of that specimen is

If x is the no of half life time then m=m02x=m016=m024No.of half live 4HereNow t=xT1/2T1/2=t4

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If a radioactive sample of mass m reduces to $\frac{m}{16}$ in time t, half life of that specimen is

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Detailed Solution

If x is the no of half life time then

$m = \frac{m_{0}}{2^{x}} = \frac{m_{0}}{16} = \frac{m_{0}}{2^{4}}$

No.of half live 4

Here

Now $t = x T_{1 / 2}$

$T_{1 / 2} = \frac{t}{4}$

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If a radioactive sample of mass m reduces to $\frac{m}{16}$ in time t, half life of that specimen is