Q.

If a slab of insulating material 4×10-3 m thick is introduced between the plates of a parallel plate capacitor, the separation between plates has to be increased by 3.5×10-3 m to restore the capacity to original value. The dielectric constant of the material will be

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a

8

b

12

c

10

d

6

answer is B.

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Detailed Solution

We have,  ε0Ad=ε0A(d+Δd)-t+tK  or  K=tt-Δd

Dielectric constant, K=4×10-34×10-3-3.5×10-3

               K=4×10-30.5×10-3=405=8K=8

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