Q.

If a solution is 0.1 M with respect to H2S and 0.5 M with respect to HCl then the concentrtion of S2 in the solution is x x 10-22 M. Find the value of x.

Given : Ka1=107Ka2=1014H2S

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answer is 4.

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Detailed Solution

Total hydrogen ion,

H+total =H+HCl=0.5MKa1+Ka2=H+2×S2H2S1021=52×102S2101S2=4×1022

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If a solution is 0.1 M with respect to H2S and 0.5 M with respect to HCl then the concentrtion of S2− in the solution is x x 10-22 M. Find the value of x.Given : Ka1=10−7Ka2=10−14H2S