If a source of power 4kW produces 1020 photons/second, the radiation belong to a part of the spectrum called

4 × 103 = 1020 × hff=4×1031020×6.023×10−34f = 6.03 × 1016HzThe obtained frequency lies in the band of X-rays

If a source of power 4kW produces 1020 photons/second, the radiation belong to a part of the spectrum called

4 × 103 = 1020 × hff=4×1031020×6.023×10−34f = 6.03 × 1016HzThe obtained frequency lies in the band of X-rays

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If a source of power 4kW produces 10²⁰ photons/second, the radiation belong to a part of the spectrum called

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$γ$ –rays

ultraviolet rays

X-rays

microwaves

answer is A.

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4 × 10³ = 10²⁰ × hf
$f = \frac{4 \times 10^{3}}{10^{20} \times 6.023 \times 10^{- 34}}$
f = 6.03 × 10¹⁶Hz
The obtained frequency lies in the band of X-rays

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If a source of power 4kW produces 10²⁰ photons/second, the radiation belong to a part of the spectrum called