Q.

If a square matrix A=aij,aij=i2j24 is of even order then

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a

|A| is a perfect square

b

A is symmetric and |A| = 0

c

A is a skew - symmetric

d

A is neither symmetric nor skew symmetric

answer is A, B.

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Detailed Solution

=0-34340
Which is a skew – symmetric.
Also, |A| is  perfect square.

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