If a surface has work function of 3.00 eV, the longest wavelength of light which will cause the emission of electrons is

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$6.84 \times 10^{- 7} m$

$4.8 \times 10^{- 7} m$

$5.99 \times 10^{- 7} m$

$4.13 \times 10^{- 7} m$

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{h c}{λ_{max}} = 3 \times 1.6 \times 10^{- 19} J \\ \Rightarrow λ_{max} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{3 \times 1.6 \times 10^{- 19}} = 4.125 \times 10^{- 7} m \end{array}$

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