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Q.

If a tangent to the parabola y2=ax makes an angle 45° with x-axis, its point of contact will be

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a

(a/2,a/4)

b

(a/4,a/2)

c

(a/2,a/4)

d

(a/4,a/2)

answer is C.

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Detailed Solution

  m=tan45=1,4A=a  ⇒ A=a/4point of contact=(Am2,2Am)                             =(a4,a2)

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