If a triangle ΔABC is an obtuse-angled triangle in which ∠C=110 then which one of the following is true

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AB > AC

AB < AC

AB > BC

AB = AC

answer is A.

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Detailed Solution

In ∆ ABC ∠ A + ∠ B + ∠ C = 180

∠ A + ∠ B + 110 = 180

∠ A + ∠ B = 180 - 110 = 70

Here sum of two angles A&B is 70 that means less than 90
So,

∠ A ∠ Bare acute angles .

By the property of the triangle,
the side opposite to the greater angle is longer.
Question Image

We are assuming that triangle may be given in the figure
As ∠C is the greatest angle so, the side opposite to ∠C is AB
So, we can say that the side AB >AC.

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