If A={0,1,2};B={1,3} and C={2,4} then (A−B)×(A−C)=

A−B={0,1,2}−{1,3} ={0,2} A−C={0,1} (A−B)×(A−C)={0,2}×{0,1} ={(0,0)(0,1)(2,0)(2,1)}

If A={0,1,2};B={1,3} and C={2,4} then (A−B)×(A−C)=

A−B={0,1,2}−{1,3} ={0,2} A−C={0,1} (A−B)×(A−C)={0,2}×{0,1} ={(0,0)(0,1)(2,0)(2,1)}

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If $A = {0, 1, 2}; B = {1, 3}$ and $C = {2, 4}$ then $(A - B) \times (A - C) =$

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{(2, 4)}

{(0, 0), (0, 1), (2, 0), (2, 1)}

{(0, 0), (1, 0), (0, 2), (1, 2)}

{(4, 2)}

answer is B.

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Detailed Solution

A - B = {0, 1, 2} - {1, 3}

$= {0, 2}$

$A - C = {0, 1}$

$(A - B) \times (A - C) = {0, 2} \times {0, 1}$

$= {(0, 0) (0, 1) (2, 0) (2, 1)}$

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If A={0,1,2};B={1,3} and C={2,4} then (A−B)×(A−C)=

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If $A = {0, 1, 2}; B = {1, 3}$ and $C = {2, 4}$ then $(A - B) \times (A - C) =$