Q.

If a1, a2, a3, a4, a5 are in H.P then a1a2 + a2a3 + a3a4 + a4a5 is equal to

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a

–4

b

2a1a5

c

4a1a5

d

3a1a5

answer is C.

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Detailed Solution

1a21a1=1a31a2=1a41a3=1a51a4=da1a2+a2a3+a3a4+a4a5=a1a5dand1a5=1a1+4da1a5=4da1a5a1a5d=4a1a5

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