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Q.

If A1,A2,........,An are the vertices of a regular plane polygon with n sides and O is the centre then i=1n1OAi¯×OAi+1¯=

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a

n1OA2¯×OA1¯

b

n+1OA2¯×OA1¯

c

n1OA1¯×OA2¯

d

n+2OA2¯×OA1¯

answer is C.

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Detailed Solution

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Now OA1×OA2  =OA1OA2  sinθ n^  OA1,OA2,.........OAn  will be of same length and subtend same angle at the centre    i=1n-1 (OAi ×OAi+1)  =(n-1)OA1OA2  sinθ n^                                            =(n-1)(OA1×OA2)

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