If A=122230012 and adj A =6-2-6-42xy-1-1, then x,y are

x=co-factor of '1' =−1220=−(0−4)=4y=co-factor of '2'=+2301=2−0=2

If A=122230012 and adj A =6-2-6-42xy-1-1, then x,y are

x=co-factor of '1' =−1220=−(0−4)=4y=co-factor of '2'=+2301=2−0=2

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If $A = [\begin{matrix} 1 & 2 & 2 \\ 2 & 3 & 0 \\ 0 & 1 & 2 \end{matrix}]$ and $a d j A = [\begin{matrix} 6 & - 2 & - 6 \\ - 4 & 2 & x \\ y & - 1 & - 1 \end{matrix}]$ , then $x, y$ are

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$x = 4$

$y = 2$

$x = 3$

$y = 5$

answer is A, B.

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$x = co-factor of '1' = - |\begin{matrix} 1 & 2 \\ 2 & 0 \end{matrix}| = - (0 - 4) = 4$

$y = co-factor of '2'=+ |\begin{matrix} 2 & 3 \\ 0 & 1 \end{matrix}| = 2 - 0 = 2$

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If A=122230012 and adj A =6-2-6-42xy-1-1, then x,y are

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If $A = [\begin{matrix} 1 & 2 & 2 \\ 2 & 3 & 0 \\ 0 & 1 & 2 \end{matrix}]$ and $a d j A = [\begin{matrix} 6 & - 2 & - 6 \\ - 4 & 2 & x \\ y & - 1 & - 1 \end{matrix}]$ , then $x, y$ are