If A=[123],B=23−1 and (A+BT)T=abc then the ascending order of a,b,c is

(A+BT)T=[(123)+(23−1)]T=[352]T=352=abcAscending order of a,b,c is c,a,b

If A=[123],B=23−1 and (A+BT)T=abc then the ascending order of a,b,c is

(A+BT)T=[(123)+(23−1)]T=[352]T=352=abcAscending order of a,b,c is c,a,b

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If $A = [\begin{matrix} 1 & 2 & 3 \end{matrix}], B = [\begin{matrix} 2 \\ 3 \\ - 1 \end{matrix}]$ and ${(A + B^{T})}^{T} = [\begin{matrix} a \\ b \\ c \end{matrix}]$ then the ascending order of $a, b, c$ is

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$a, b, c$

$b, c, a$

$c, a, b$

$c, b, a$

answer is C.

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Detailed Solution

${(A + B^{T})}^{T} = {[(\begin{matrix} 1 & 2 & 3 \end{matrix}) + (\begin{matrix} 2 & 3 & - 1 \end{matrix})]}^{T}$

$= {[\begin{matrix} 3 & 5 & 2 \end{matrix}]}^{T}$

$= [\begin{matrix} 3 \\ 5 \\ 2 \end{matrix}]$

$= [\begin{matrix} a \\ b \\ c \end{matrix}]$

Ascending order of $a, b, c$ is $c, a, b$

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If A=[123],B=23−1 and (A+BT)T=abc then the ascending order of a,b,c is

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If $A = [\begin{matrix} 1 & 2 & 3 \end{matrix}], B = [\begin{matrix} 2 \\ 3 \\ - 1 \end{matrix}]$ and ${(A + B^{T})}^{T} = [\begin{matrix} a \\ b \\ c \end{matrix}]$ then the ascending order of $a, b, c$ is