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If $a = 16$ and $b = 9$ , then the rational number is

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\sqrt{a + b}

\sqrt{a b}

\sqrt{\frac{a}{b}}

\sqrt{a - b}

answer is D.

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Detailed Solution

a = 16, b = 9

A) $\sqrt{a + 16} = \sqrt{16 + 9} = \sqrt{25} = 5$ (rational)

B) $\sqrt{a b} = \sqrt{16 \times 9} = 4 \times 3 = 12$ (rational)

C) $\sqrt{a - b} = \sqrt{16 - 9} = \sqrt{7}$ (irrational)

D) $\sqrt{\frac{a}{b}} = \sqrt{\frac{16}{9}} = \frac{4}{3}$ (rational)

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