If A=(22−32),B=(0−110) , then (B−1A−1)−1=

(B−1A−1)−1=(A−1)−1(B−1)−1=AB =(2−223)

If A=(22−32),B=(0−110) , then (B−1A−1)−1=

(B−1A−1)−1=(A−1)−1(B−1)−1=AB =(2−223)

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If $A = (\begin{matrix} 2 & 2 \\ - 3 & 2 \end{matrix}), B = (\begin{matrix} 0 & - 1 \\ 1 & 0 \end{matrix})$ , then ${(B^{- 1} A^{- 1})}^{- 1} =$

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(\begin{matrix} 2 & - 2 \\ 2 & 3 \end{matrix})

(\begin{matrix} 3 & - 2 \\ 2 & 2 \end{matrix})

\frac{1}{10} (\begin{matrix} 2 & 2 \\ - 2 & 3 \end{matrix})

\frac{1}{10} (\begin{matrix} 3 & 2 \\ - 2 & 2 \end{matrix})

answer is A.

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{(B^{- 1} A^{- 1})}^{- 1} = {(A^{- 1})}^{- 1} {(B^{- 1})}^{- 1} = A B

$= (\begin{matrix} 2 & - 2 \\ 2 & 3 \end{matrix})$

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If A=(22−32),B=(0−110) , then (B−1A−1)−1=

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If $A = (\begin{matrix} 2 & 2 \\ - 3 & 2 \end{matrix}), B = (\begin{matrix} 0 & - 1 \\ 1 & 0 \end{matrix})$ , then ${(B^{- 1} A^{- 1})}^{- 1} =$