If $A-2B=\left[\begin{array}{c}15\\ 37\end{array}\right]$ and $2A-3B=\left[\begin{array}{c}-25\\ 07\end{array}\right]$ , then B is

Solve (1) and (2)

$2A-4B=\left[\begin{array}{c}210\\ 614\end{array}\right]$

$\underset{\_}{2A-3B=\left[\begin{array}{c}-25\\ 07\end{array}\right]}$

         $-B=\left[\begin{array}{c}45\\ 67\end{array}\right]$

$\therefore B=-\left[\begin{array}{c}45\\ 67\end{array}\right]$