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Q.

If $a \sqrt{2} + b \sqrt{2} = \sqrt{50}$ , where a, $b \in N$ then the number of possible ordered pairs of the form $(a, b)$ can be obtained is

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a

4

b

5

c

3

d

2

answer is B.

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Detailed Solution

a \sqrt{2} + b \sqrt{2} = \sqrt{50}

$\Rightarrow (a + b) \sqrt{2} = \sqrt{25 \times 2}$

$\Rightarrow (a + b) \sqrt{2} = 5 \sqrt{2}$

$a + b = 5$

$(1, 4), (3, 2), (4, 1), (2, 3)$

The number of order pairs are 4.

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