If A→=2i^+3j^+4k^ and B→=4i^+3j^+2k^ then A→×B→ is

A¯×B¯=ijk234432=−6i^+12j^−6k^

If A→=2i^+3j^+4k^ and B→=4i^+3j^+2k^ then A→×B→ is

A¯×B¯=ijk234432=−6i^+12j^−6k^

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If $\vec{A} = 2 \hat{i} + 3 \hat{j} + 4 \hat{k} and \vec{B} = 4 \hat{i} + 3 \hat{j} + 2 \hat{k} then \vec{A} \times \vec{B}$ is

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$- 6 \hat{i} + 12 \hat{j} - 6 \hat{k}$

$3 \hat{i} + 4 \hat{j} - 6 \hat{k}$

$6 \hat{i} + 24 \hat{j} - 14 \hat{k}$

$3 \hat{i} - 8 \hat{j} + 2 \hat{k}$

answer is A.

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$\bar{A} \times \bar{B} = |\begin{matrix} i & j & k \\ 2 & 3 & 4 \\ 4 & 3 & 2 \end{matrix}|$

$= - 6 \hat{i} + 12 \hat{j} - 6 \hat{k}$

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If A→=2i^+3j^+4k^ and B→=4i^+3j^+2k^ then A→×B→ is

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If $\vec{A} = 2 \hat{i} + 3 \hat{j} + 4 \hat{k} and \vec{B} = 4 \hat{i} + 3 \hat{j} + 2 \hat{k} then \vec{A} \times \vec{B}$ is