If A=[6−2−41] , then 7A+2I is

7A+2I =7[6−2−41]+2[1001]=[44−14−289] A2=[6−2−41]×[6−2−41] =[6(6)+(−2)(−4)6(−2)+(−2)(1)−4(6)+1(−4)−4(−2)+(1)(1)] =[44−14−289] ∴7A+2I=A2

If A=[6−2−41] , then 7A+2I is

7A+2I =7[6−2−41]+2[1001]=[44−14−289] A2=[6−2−41]×[6−2−41] =[6(6)+(−2)(−4)6(−2)+(−2)(1)−4(6)+1(−4)−4(−2)+(1)(1)] =[44−14−289] ∴7A+2I=A2

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If $A = [\begin{matrix} 6 & - 2 \\ - 4 & 1 \end{matrix}]$ , then $7 A + 2 I$ is

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A A^{T}

A A^{- 1}

A^{3}

A^{2}

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7 A + 2 I

= 7 [\begin{matrix} 6 & - 2 \\ - 4 & 1 \end{matrix}] + 2 [\begin{matrix} 1 & 0 \\ 0 & 1 \end{matrix}] = [\begin{matrix} 44 & - 14 \\ - 28 & 9 \end{matrix}]

$A^{2} = [\begin{matrix} 6 & - 2 \\ - 4 & 1 \end{matrix}] \times [\begin{matrix} 6 & - 2 \\ - 4 & 1 \end{matrix}]$

$= [\begin{matrix} 6 (6) + (- 2) (- 4) & 6 (- 2) + (- 2) (1) \\ - 4 (6) + 1 (- 4) & - 4 (- 2) + (1) (1) \end{matrix}]$

$= [\begin{matrix} 44 & - 14 \\ - 28 & 9 \end{matrix}]$

$∴ 7 A + 2 I = A^{2}$

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If $A = [\begin{matrix} 6 & - 2 \\ - 4 & 1 \end{matrix}]$ , then $7 A + 2 I$ is