If A(6,3), B(–3,5), C(4,–2) and P(a,b) then the ratio of the areas of the triangles PBC, ABC is

$\text{ Area of triangle}=\frac{1}{2}\left|\begin{array}{l}{x}_1-x_2\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{y}_1-y_2\\ x_1-x_3\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{y}_1-y_3\end{array}\right|$

$\Rightarrow P(a,b),A=(6,3),B(-3,5),C=(4,-2)$

$\text{ Area of }\mathrm{△}PBC:\text{ Area of }\mathrm{△}ABC$

$\frac{1}{2}|7a+7b-14|:\frac{1}{2}49\Rightarrow |a+b-2|:7$